hours

Source: utils/date_time/hours.pro

 HOURS
        returns the difference in hours between two times.

 Usage;
        dt = hours(t1, t0)

 Return Value:
        dt      float   The difference in hours between the two times.

 Arguments:
        t1      int/float       input   The "later" time in array [y,d,h,m,s]
        t0      int/float       input   The "earlier" time

 Method:
        Returns t1 - t0 with due allowance for leap years.

 History:
        Original: 7/6/93; SJT
        Fix negative difference crossing year boundary: 28/10/93; SJT
        Fix for century boundary: 1/12/95; SJT
        Make double to allow sub-second accuracy over whole mission:
        16/11/99; SJT